Solution
By the exterior angle theorem:
2x = ∠2 + 40 → ∠2 = 2x - 40
2y = ∠1 + 40 → ∠1 = 2y - 40
∠1 + ∠2 = 2x + 2y - 80
But ∠1 + ∠2 = 180 - 40 = 140
140 = 2x + 2y - 80
2x + 2y = 220 → x + y = 110
z = 180 - (x + y) = 180 - 110 = 70
So the measure of ∠ADB = z is 70°, no matter where A and B are placed.